48=e^2/12

Solution for 48=e^2/12 equation:

48=e^2/12

We move all terms to the left:

48-(e^2/12)=0

We get rid of parentheses

-e^2/12+48=0

We multiply all the terms by the denominator


-e^2+48*12=0

We add all the numbers together, and all the variables

-1e^2+576=0

a = -1; b = 0; c = +576;
Δ = b2-4ac
Δ = 02-4·(-1)·576
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-1}=\frac{-48}{-2}
=+24
$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-1}=\frac{48}{-2}
=-24
$